20v^2+84v+12=-4

Solution for 20v^2+84v+12=-4 equation:

20v^2+84v+12=-4

We move all terms to the left:

20v^2+84v+12-(-4)=0

We add all the numbers together, and all the variables

20v^2+84v+16=0

a = 20; b = 84; c = +16;
Δ = b2-4ac
Δ = 842-4·20·16
Δ = 5776
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{5776}=76$
$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(84)-76}{2*20}=\frac{-160}{40}
=-4
$
$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(84)+76}{2*20}=\frac{-8}{40}
=-1/5
$